1. In the following reaction, how many grams of pentyl alcohol (C5H11OH) would be required to react completely with 2.42 x 1025 oxygen molecules? Next, if 0.135 grams of water were formed in this reaction, how many CO2 molecules would have been formed? C5H11OH + O2 —–> CO2 + H2O2. By now, you all know that silver iodide is very insoluble in water. Chemists know that by adding a very slight excess of silver nitrate to an iodide containing solution it is possible effectively to remove all the iodide ion from the sample. First, write a balanced net ionic equation for this reaction. Then, assume that a sample has a mass of 12.375 grams contains 39.3% iodide ion by mass. Then, calculate the mass of silver nitrate must be used to completely precipitate all the iodide from the sample.3. A sample of copper was heated to 275oC and placed into 275 grams of water at 21.0oC. The water temperature rose to 29.7oC. What was the mass of the copper sample? Specific heat capacity of water = 4.184 Joules/gram/oC and for copper, 0.385 Joules/gram/oC.4. A 10.00 gram mixture of NaHCO3 and Na2CO3 was heated and yielded 0.0357 moles of H2O and 0.1091 moles of CO2. Calculate the percent composition of the mixture is the reactions are described by: NaHCO3 —–> Na2O + CO2 + H2O and Na2CO3 —–> Na2O + CO2.5. A 225 gram sample of aluminum was heated to 125.5oC, then placed into 500.0 grams of water at 22.5oC. If the specific heat of aluminum is 0.900 Joules/gram/oC, what is the final temperature of the water?6. Diborane, B2H6(g) cannot be made directly from boron and hydrogen, but is Hfo can be determined from the following thermodynamic data. Using the following reactions, calculate the enthalpy of formation (Hfo) of diborane. 1) 4B(s) + 3O2(g) —–> 2B2O3(s) Hfo = -2547.0 kJ/mole 2) H2(g) + 1/2O2(g) —–> H2O(l) Hfo = -285.8 kJ/mole 3) B2H6(g) + 3O2(g) —–> B2O3(s) + 3H2O(l) Hfo = -2167.3 kJ/mole7. In the unbalanced reaction, Mn + HNO3 —–> Mn(NO3)4 + N2O+ H2O, 3.050 grams of Mn(NO3)4 was formed. How many grams of N2O were formed and how many HNO3 molecules were used up in the reaction8. When a calcium carbonate tablet is ingested, it dissolves by the reaction of stomach acid, which contains hydrochloric acid. The unbalanced equation for this reaction is CaCO3(s) + HCl(aq) —–> CaCl2(aq) + H2O(l) + CO2(g). Normal stomach acid contains 5.50% hydrochloric acid. If a particular individual required 13 calcium carbonate tablets to completely neutralize their stomach acid, how many grams of stomach acid reacted? Each calcium carbonate tablet contains 500. mg of the active ingredient9. Tin (IV) chloride can be made by heating tin in an atmosphere of excess dry chlorine. If the percentage yield of this process is 64.3%, how many grams of tin are required to produce 1.060 grams of SnCl4(l)?10. In the reaction of copper with potassium dichromate and sulfuric acid, the products are copper (I) sulfate, potassium sulfate, water, and chromium (III) sulfate. First, write a balanced net ionic equation for this reaction. Then consider the reaction taking place with 125.0 grams of copper, 150.0 grams of potassium dichromate, and 400.0 grams of sulfuric acid. How many grams of potassium sulfate could be produced in this reaction?
Grams of Pentyl Alcohol & Oxygen Molecules Questions